i thought that too initially, but:
let's say that a true ASR's steps are empty of voltages.
first step is filled with voltage 'X'.
in the next trigger, that voltage 'X' is moved to step two and a new voltage 'Y' fills the first step. in the next trigger, the voltage 'X' fills the step three, the voltage 'Y' fills the step two and the new voltage fills the first step. that's how a true ASR works.
so, in a true ASR, the new voltage fills the first step and the older voltages go down one step in the chain.
the A152 fills the first step with the last present voltage in it, when a clock pulse was received, or a new step was addressed. the currently present voltage, that is now in the second step, will fill the SECOND step, with the exact value it had when the clock pulse was received, after a new clock pulse is received. then, the currently presented voltage that is in the third step now, at the next clock pulse, will fill the THIRD step with its exact value when the clock pulse was received. also, each output tracks the current voltage until a clock pulse is received, so it is a T/H and not a S/H unit.
so, in the A152, the new voltage fills the NEXT step and the old voltages remain at the steps they were.
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--- On Sun, 12/28/08, Axel Jungkunst <
phaedra@...
> wrote:
From: Axel Jungkunst <
phaedra@...
>
Subject: Re: 1 Re: Doepfer A-152 question
To:
Doepfer_a100@yahoogroups.com
Date: Sunday, December 28, 2008, 9:18 PM
But it matches my patching, try it out!
Doug schrieb:
>
> What you are describing is great, and would constitute an ASR, but it
> doesn't match the factory description:
>
> "The signal at the common T&H input is connected to the addressed T&H
> output. As soon as a new output is addressed the last voltage is
> stored at the output (Track&Hold function)."
>
> --- In Doepfer_a100@ yahoogroups. com
> <mailto:Doepfer_ a100%40yahoogrou ps.com>, Axel Jungkunst <phaedra@... >
> wrote:
> >
> > Now I see the error in your explanation: the incoming voltage is not
> > distributed to all
> > 8 S/H outputs, but to the first one. Each incoming pulse shifts it one
> > S/H-Output further
> > and fills the first one with the new state.
> > You can terminate the number of outputs by using a digital out to the
> > reset in (look at the example).
> > Try it out, I've done it, it works fine.
> > best regards
> > Axel
> >
>
>
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