If it's like the A-133, I find the 'zero' point to be very small. Same with the Polarizing mixer.

Neil

Sent from my iPhone

On 5 Feb 2015, at 03:14, raulpena1974@... 1 < Doepfer_a100@yahoogroups.com > wrote:

 

Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.

As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.

Can anyone confirm this behavior or explain if I am misunderstanding something

Thanks for any help.

Raul